Regex to Match Symbols: !$%^&*()_+|~-=`{}[]:";'<>?,./

I'm trying to create a Regex test in JavaScript that will test a string to contain any of these characters:


More Info If You're Interested :)

It's for a pretty cool password change application I'm working on. In case you're interested here's the rest of the code.

I have a table that lists password requirements and as end-users types the new password, it will test an array of Regexes and place a checkmark in the corresponding table row if it... checks out :) I just need to add this one in place of the 4th item in the validation array.

var validate = function(password){
    valid = true;

    var validation = [
        RegExp(/[a-z]/).test(password), RegExp(/[A-Z]/).test(password), RegExp(/\d/).test(password), 
        RegExp(/\W|_/).test(password), !RegExp(/\s/).test(password), !RegExp("12345678").test(password), 
        !RegExp($('#txtUsername').val()).test(password), !RegExp("cisco").test(password), 
        !RegExp(/([a-z]|[0-9])\1\1\1/).test(password), (password.length > 7)

    $.each(validation, function(i){
            $('.form table tr').eq(i+1).attr('class', 'check');
            $('.form table tr').eq(i+1).attr('class', '');
            valid = false



Yes, there's also corresponding server-side validation!

The regular expression for this is really simple. Just use a character class. The hyphen is a special character in character classes, so it needs to be first:


You also need to escape the other regular expression metacharacters.

Edit: The hyphen is special because it can be used to represent a range of characters. This same character class can be simplified with ranges to this:


There are three ranges. '$' to '/', ':' to '?', and '{' to '~'. the last string of characters can't be represented more simply with a range: !"^_`[].

Use an ACSII table to find ranges for character classes.

The most simple and shortest way is to use this:


It means: All characters that are not a digit or an English letter (\W) or a white-space character (\S).

It maybe is not as perfect as Jeff's solution, but it's much simpler and I don't think it differs in practicality.

// The string must contain at least one special character, escaping reserved RegEx characters to avoid conflict
  const hasSpecial = password => {
    const specialReg = new RegExp(
      '^(?=.*[[email protected]#$%^&*"\\[\\]\\{\\}<>/\\(\\)=\\\\\\-_´+`~\\:;,\\.€\\|])',
    return specialReg.test(password);

A simple way to achieve this is the negative set [^\w\s]. This essentially catches:

  • Anything that is not an alphanumeric character (letters and numbers)
  • Anything that is not a space, tab, or line break (collectively referred to as whitespace)

For some reason [\W\S] does not work the same way, it doesn't do any filtering. A comment by Zael on one of the answers provides something of an explanation.

Replace all latters from any language in 'A', and if you wish for example all digits to 0:

return str.replace(/[^\[email protected][-`{-~]/g, "A").replace(/\d/g, "0");




This creates a negated character class removing the word characters and space characters. All that is left is the special characters.

\w will select all "word" characters equivalent to [^a-zA-Z0-9_]
\s will select all "whitespace" characters equivalent to [ \t\n\r\f\v]

adding the ^ at the beginning of the class says to not select any of the following.