# How to format numbers by prepending 0 to single-digit numbers?

I want to format a number to have two digits. The problem is caused when `0``9` is passed, so I need it to be formatted to `00``09`.

Is there a number formatter in JavaScript?

The best method I've found is something like the following:

(Note that this simple version only works for positive integers)

``````var myNumber = 7;
var formattedNumber = ("0" + myNumber).slice(-2);
console.log(formattedNumber);``````

For decimals, you could use this code (it's a bit sloppy though).

``````var myNumber = 7.5;
var dec = myNumber - Math.floor(myNumber);
myNumber = myNumber - dec;
var formattedNumber = ("0" + myNumber).slice(-2) + dec.toString().substr(1);
console.log(formattedNumber);``````

Lastly, if you're having to deal with the possibility of negative numbers, it's best to store the sign, apply the formatting to the absolute value of the number, and reapply the sign after the fact. Note that this method doesn't restrict the number to 2 total digits. Instead it only restricts the number to the left of the decimal (the integer part). (The line that determines the sign was found here).

``````var myNumber = -7.2345;
var sign = myNumber?myNumber<0?-1:1:0;
myNumber = myNumber * sign + ''; // poor man's absolute value
var dec = myNumber.match(/\.\d+\$/);
var int = myNumber.match(/^[^\.]+/);

var formattedNumber = (sign < 0 ? '-' : '') + ("0" + int).slice(-2) + (dec !== null ? dec : '');
console.log(formattedNumber);``````

If the number is higher than 9, convert the number to a string (consistency). Otherwise, add a zero.

``````function n(n){
return n > 9 ? "" + n: "0" + n;
}

n( 9); //Returns "09"
n(10); //Returns "10"
n(999);//Returns "999"
``````

Use the toLocaleString() method in any number. So for the number 6, as seen below, you can get the desired results.

``````(6).toLocaleString('en-US', {minimumIntegerDigits: 2, useGrouping:false})
``````

Will generate the string '06'.

Here's a simple number padding function that I use usually. It allows for any amount of padding.

``````function leftPad(number, targetLength) {
var output = number + '';
while (output.length < targetLength) {
output = '0' + output;
}
return output;
}
``````

Examples:

``````leftPad(1, 2) // 01
``````

In all modern browsers you can use

``````numberStr.padStart(2, "0");
``````

``````function zeroPad(numberStr) {
}

var numbers = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10];

numbers.forEach(
function(num) {
var numString = num.toString();

}
);``````

@Lifehack's answer was very useful to me; where I think we can do it in one line for positive numbers

`````` String(input).padStart(2, '0');
``````

``````("0" + (date.getMonth() +?1)).slice(-2);
("0" + (date.getDay())).slice(-2);
``````

You can do:

``````function pad2(number) {
return (number < 10 ? '0' : '') + number
}
``````

Example:

``````document.write(pad2(0) + '<br />');
``````

Result:

``````00
01
02
10
15
``````

It seems you might have a string, instead of a number. use this:

``````var num = document.getElementById('input').value,
replacement = num.replace(/^(\d)\$/, '0\$1');
document.getElementById('input').value = replacement;
``````

Here's an example: http://jsfiddle.net/xtgFp/

Quick and dirty one liner....

``````function zpad(n, len) {
return 0..toFixed(len).slice(2,-n.toString().length)+n.toString();
}
``````

This is simple and works pretty well:

``````function twoDigit(number) {
var twodigit = number >= 10 ? number : "0"+number.toString();
return twodigit;
}
``````

Here is a very simple solution that worked well for me.

First declare a variable to hold your number.

``````var number;
``````

Now convert the number to a string and hold it in another variable;

``````var numberStr = number.toString();
``````

Now you can test the length of this string , if it is less than desired you can append a 'zero' at the beginning.

``````if(numberStr.length < 2){
number = '0' + number;
}
``````

Now use the number as desired

``````console.log(number);
``````

Here's the easiest solution I found:-

``````let num = 9; // any number between 0 & 99
let result = ( '0' + num ).substr( -2 );
``````

``````function atLeast2Digit(n){
n = parseInt(n); //ex. if already passed '05' it will be converted to number 5
var ret = n > 9 ? "" + n: "0" + n;
return ret;
}

I know this is an ancient post, but I wanted to provide a more flexible and OO solution option.

I've extrapolated the accepted answer a bit and extended javascript's `Number` object to allow for adjustable zero padding:

``````Number.prototype.zeroPad = function(digits) {
var loop = digits;
var zeros = "";
while (loop) {
zeros += "0";
loop--;
}
return (this.toString().length > digits) ?
this.toString() : (zeros + this).slice(-digits);
}
var v = 5;

Edit: Add code to prevent cutting off numbers longer than your requested digits.

NOTE: This is obsolete in all but IE. Use `padStart()` instead.

There is not a built-in number formatter for JavaScript, but there are some libraries that accomplish this:

1. underscore.string provides an sprintf function (along with many other useful formatters)
2. javascript-sprintf, which underscore.string borrows from.

or

``````function zpad(n,l){
return rep(l-n.toString().length, '0') + n.toString();
}
``````

with

``````function rep(len, chr) {
return new Array(len+1).join(chr);
}
``````

If you want to limit your digits at the same time:

``````function pad2(number) {
number = (number < 10 ? '0' : '') + number;
number = number.substring(0,2);
return number;
}
``````

This would also chop of any value that exceeds two digits. I have been extending this upon fanaur's solution.

``````<html>
<script src="http://code.jquery.com/jquery-1.11.0.min.js"></script>
<script type="text/javascript">
\$('#test').keypress(allowOnlyTwoPositiveDigts);
});

function allowOnlyTwoPositiveDigts(e){

var test = /^[\-]?[0-9]{1,2}?\$/
return test.test(this.value+String.fromCharCode(e.which))
}

</script>
<body>
<input id="test" type="text" />
</body>
</html>
``````

Here's a simple recursive solution that works for any number of digits.

``````function numToNDigitStr(num, n)
{
if(num >=  Math.pow(10, n - 1)) { return num; }
return "0" + numToNDigitStr(num, n-1);
}
``````

If you don't have lodash in your project it will be an overkill to add the whole library just to use one function. This is the most sophisticated solution of your problem I've ever seen.

``````_.padStart(num, 2, '0')
``````

Here's my version. Can easily be adapted to other scenarios.

``````function setNumericFormat(value) {
var length = value.toString().length;
if (length < 4) {
var prefix = "";
for (var i = 1; i <= 4 - length; i++) {
prefix += "0";
}
return prefix + value.toString();
}
return  value.toString();
}
``````

``````    function colorOf(r,g,b){
var f = function (x) {
return (x<16 ? '0' : '') + x.toString(16)
};

return "#" +  f(r) + f(g) + f(b);
}
``````

For anyone who wants to have time differences and have results that can take negative numbers here is a good one. pad(3) = "03", pad(-2) = "-02", pad(-234) = "-234"

``````pad = function(n){
if(n >= 0){
return n > 9 ? "" + n : "0" + n;
}else{
return n < -9 ? "" + n : "-0" + Math.abs(n);
}
}
``````

with this function you can print with any n digits you want

``````function frmtDigit(num, n) {
isMinus = num < 0;
if (isMinus)
num *= -1;
digit = '';
if (typeof n == 'undefined')
n = 2;//two digits
for (i = 1; i < n; i++) {
if (num < (1 + Array(i + 1).join("0")))
digit += '0';
}
digit = (isMinus ? '-' : '') + digit + num;
return digit;
};
``````

my example would be:

``````<div id="showTime"></div>

function x() {
var showTime = document.getElementById("showTime");
var myTime = new Date();
var hour = myTime.getHours();
var minu = myTime.getMinutes();
var secs = myTime.getSeconds();
if (hour < 10) {
hour = "0" + hour
};
if (minu < 10) {
minu = "0" + minu
};
if (secs < 10) {
secs = "0" + secs
};

showTime.innerHTML = hour + ":" + minu + ":" + secs;
}

setInterval("x()", 1000)
``````

``\${number}`.replace(/^(\d)\$/, '0\$1');`

Regex is the best.

AS datatype in Javascript are determined dynamically it treats 04 as 4 Use conditional statement if value is lesser then 10 then add 0 before it by make it string E.g,

``````var x=4;
x = x<10?"0"+x:x
console.log(x); // 04
``````

I built a pretty simple format function that I call whenever I need a simple date formatted. It deals with formatting single digits to double digits when they're less than 10. It kicks out a date formatted as `Sat Sep 29 2018 - 00:05:44`

This function is used as part of a utils variable so it's called as:

``````let timestamp = utils._dateFormatter('your date string');

var utils = {
_dateFormatter: function(dateString) {
let d = new Date(dateString);
let hours = d.getHours();
let minutes = d.getMinutes();
let seconds = d.getSeconds();
d = d.toDateString();
if (hours < 10) {
hours = '0' + hours;
}
if (minutes < 10) {
minutes = '0' + minutes;
}
if (seconds < 10) {
seconds = '0' + seconds;
}
let formattedDate = d + ' - ' + hours + ':' + minutes + ':' + seconds;
return formattedDate;
}
}
``````

Updated for ES6 Arrow Functions (Supported in almost all modern browsers, see CanIUse)

``````const formatNumber = n => ("0" + n).slice(-2);
``````

My version:

```````\${Math.trunc(num / 10)}\${Math.trunc(num % 10)}`;
``````

``````const func = (num) => `\${Math.trunc(num / 10)}\${Math.trunc(num % 10)}`;

const nums = [1, 3, 5, 6, 8, 9, 20, 56, 80];
nums.forEach(num => console.log(func(num)));``````