Regular Expression to get a string between parentheses in Javascript


I am trying to write a regular expression which returns a string which is between parentheses. For example: I want to get the string which resides between the strings "(" and ")"

I expect five hundred dollars ($500).

would return

$500

Found Regular Expression to get a string between two strings in Javascript

But I'm new with regex. I don't know how to use '(', ')' in regexp

You need to create a set of escaped (with \) parentheses (that match the parentheses) and a group of regular parentheses that create your capturing group:

var regExp = /\(([^)]+)\)/;
var matches = regExp.exec("I expect five hundred dollars ($500).");

//matches[1] contains the value between the parentheses
console.log(matches[1]);

Breakdown:

  • \( : match an opening parentheses
  • ( : begin capturing group
  • [^)]+: match one or more non ) characters
  • ) : end capturing group
  • \) : match closing parentheses

Here is a visual explanation on RegExplained


Try string manipulation:

var txt = "I expect five hundred dollars ($500). and new brackets ($600)";
var newTxt = txt.split('(');
for (var i = 1; i < newTxt.length; i++) {
    console.log(newTxt[i].split(')')[0]);
}

or regex (which is somewhat slow compare to the above)

var txt = "I expect five hundred dollars ($500). and new brackets ($600)";
var regExp = /\(([^)]+)\)/g;
var matches = txt.match(regExp);
for (var i = 0; i < matches.length; i++) {
    var str = matches[i];
    console.log(str.substring(1, str.length - 1));
}

Ported Mr_Green's answer to a functional programming style to avoid use of temporary global variables.

var matches = string2.split('[')
  .filter(function(v){ return v.indexOf(']') > -1})
  .map( function(value) { 
    return value.split(']')[0]
  })

For just digits after a currency sign : \(.+\s*\d+\s*\) should work

Or \(.+\) for anything inside brackets


Simple solution

Notice: this solution used for string that has only single "(" and ")" like string in this question.

("I expect five hundred dollars ($500).").match(/\((.*)\)/).pop();

Online demo (jsfiddle)


To match a substring inside parentheses excluding any inner parentheses you may use

\(([^()]*)\)

pattern. See the regex demo.

In JavaScript, use it like

var rx = /\(([^()]*)\)/g;

Pattern details

  • \( - a ( char
  • ([^()]*) - Capturing group 1: a negated character class matching any 0 or more chars other than ( and )
  • \) - a ) char.

To get the whole match, grab Group 0 value, if you need the text inside parentheses, grab Group 1 value:

var strs = ["I expect five hundred dollars ($500).", "I expect.. :( five hundred dollars ($500)."];
var rx = /\(([^()]*)\)/g;


for (var i=0;i<strs.length;i++) {
  console.log(strs[i]);

  // Grab Group 1 values:
  var res=[], m;
  while(m=rx.exec(strs[i])) {
    res.push(m[1]);
  }
  console.log("Group 1: ", res);

  // Grab whole values
  console.log("Whole matches: ", strs[i].match(rx));
}


var str = "I expect five hundred dollars ($500) ($1).";
var rex = /\$\d+(?=\))/;
alert(rex.exec(str));

Will match the first number starting with a $ and followed by ')'. ')' will not be part of the match. The code alerts with the first match.

var str = "I expect five hundred dollars ($500) ($1).";
var rex = /\$\d+(?=\))/g;
var matches = str.match(rex);
for (var i = 0; i < matches.length; i++)
{
    alert(matches[i]);
}

This code alerts with all the matches.

References:

search for "?=n" http://www.w3schools.com/jsref/jsref_obj_regexp.asp

search for "x(?=y)" https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Global_Objects/RegExp


let str = "Before brackets (Inside brackets) After brackets".replace(/.*\(|\).*/g, '');
console.log(str) // Inside brackets


Alternative:

var str = "I expect five hundred dollars ($500) ($1).";
str.match(/\(.*?\)/g).map(x => x.replace(/[()]/g, ""));
? (2) ["$500", "$1"]

It is possible to replace brackets with square or curly brackets if you need