How to escape regular expression special characters using javascript? [duplicate]

I need to escape the regular expression special characters using java script.How can i achieve this?Any help should be appreciated.

Thanks for your quick reply.But i need to escape all the special characters of regular expression.I have try by this code,But i can't achieve the result.

                if (!arguments.callee.sRE) {
                    var specials = [
                        '/', '.', '*', '+', '?', '|',
                        '(', ')', '[', ']', '{', '}', '\\'
                    arguments.callee.sRE = new RegExp(
                    '(\\' + specials.join('|\\') + ')', 'gim'
                return str.replace(arguments.callee.sRE, '\\$1');


function regExpFind() {
            <%--var regex = new RegExp("\\[munees\\]","gim");--%>
                    var regex= new RegExp(RegExp.escape("[Munees]waran"));
                    <%--var regex=RegExp.escape`enter code here`("[Munees]waran");--%>
                    alert("Reg : "+regex);

What i am wrong with this code?Please guide me.

Use the \ character to escape a character that has special meaning inside a regular expression.

To automate it, you could use this:

function escapeRegExp(text) {
  return text.replace(/[-[\]{}()*+?.,\\^$|#\\s]/g, '\\$&');

Update: There is now a proposal to standardize this method, possibly in ES2016:

Update: The abovementioned proposal was rejected, so keep implementing this yourself if you need it.

Use the backslash to escape a character. For example:


This will match \d instead of a numeric character

With \ you escape special characters

Escapes special characters to literal and literal characters to special.

E.g: /\(s\)/ matches '(s)' while /(\s)/ matches any whitespace and captures the match.